Write a C program to convert a given number to words

Write a C program to convert a given number to words

Program:-     

#include <stdio.h>
#include <string.h>
void convert(char *num)
{
int len = strlen(num); // find no of digit
/* no number */
if (len == 0) {
fprintf(stderr, “empty string\n”);
return;
}

char *single_digits[] = { “zero”, “one”, “two”, “three”, “four”,”five”,”six”, “seven”, “eight”, “nine”};

char *two_digits[] = {“”, “ten”, “eleven”, “twelve”, “thirteen”, “fourteen”,”fifteen”, “sixteen”,”seventeen”, “eighteen”, “nineteen”};

char *tens_multiple[] = {“”, “”, “twenty”, “thirty”, “forty”, “fifty”,
“sixty”, “seventy”, “eighty”, “ninety”};

char *tens_power[] = {“hundred”, “thousand”};
/* single number*/
if (len == 1) {
printf(“%s\n”, single_digits[*num – ‘0’]);
return;
}

while (*num != ‘\0’) {
if (len >= 3) {
if (*num -‘0’ != 0) {
printf(“%s “, single_digits[*num – ‘0’]);
printf(“%s “, tens_power[len-3]); // here len can be 3 or 4
}
–len;
}

/* Code path for last 2 digits */
else {
if (*num == ‘1’) {
int sum = *num – ‘0’ + *(num + 1)- ‘0’;
printf(“%s\n”, two_digits[sum]);
return;
}
else if (*num == ‘2’ && *(num + 1) == ‘0’) {
printf(“twenty\n”);
return;
}

/* number range 21 to 99 */
else {
int i = *num – ‘0’;
printf(“%s “, i? tens_multiple[i]: “”);
++num;
if (*num != ‘0’)
printf(“%s “, single_digits[*num – ‘0’]);
}
}
++num;
}
}

int main(void)
{
char a[10];
printf(“\nEnter the number : “);
scanf(“%s”,a);
printf(“\nThe number in word is “);
convert(a);
return 0;
}

Output:-

....

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Milan Tomic

Hi. I’m Designer of Blog Magic. I’m CEO/Founder of ThemeXpose. I’m Creative Art Director, Web Designer, UI/UX Designer, Interaction Designer, Industrial Designer, Web Developer, Business Enthusiast, StartUp Enthusiast, Speaker, Writer and Photographer. Inspired to make things looks better.

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